Maybe this is a stupid question, but is it possible to make the same Kangaroo have both odd and even DPs, like @AlexanderCurl does? Could we reach 90-bit *f* this way? That would be a cool Kangaroo Hopping!!! If BSGS is concerned one of possible ways is to divide the range according to the number of cpu cores and start the search from the middle of each interval using batch logic and calculating only X coordinate for the batch_size - 1 and the last one full (x,y). Make a database from the target point as large as your RAM can hold. Or since you know the size of each block do calculations to put the point closer to the middle. Maybe that way you can hit higher bits. But that depends on what time you have on your mind for that collision to happen. That's only useful for brute-forcing, however brute-forcing is un-needed for DLP problems. For BSGS this trick is also useless because it requires shifting the key by range/2 (to have the same-X mapping to 2 points), but the shift itself may move the point in the left side, which means the solution will never be found (unless you use two giant points instead of one, so zero benefit overall).
Maybe this is a stupid question, but is it possible to make the same Kangaroo have both odd and even DPs, like @AlexanderCurl does? Could we reach 90-bit *f* this way? That would be a cool Kangaroo Hopping!!! If BSGS is concerned one of possible ways is to divide the range according to the number of cpu cores and start the search from the middle of each interval using batch logic and calculating only X coordinate for the batch_size - 1 and the last one full (x,y). Make a database from the target point as large as your RAM can hold. Or since you know the size of each block do calculations to put the point closer to the middle. Maybe that way you can hit higher bits. But that depends on what time you have on your mind for that collision to happen. That's only useful for brute-forcing, however brute-forcing is un-needed for DLP problems. For BSGS this trick is also useless because it requires shifting the key by range/2 (to have the same-X mapping to 2 points), but the shift itself may move the point in the left side, which means the solution will never be found (unless you use two giant points instead of one, so zero benefit overall).

Maybe this is a stupid question, but is it possible to make the same Kangaroo have both odd and even DPs, like @AlexanderCurl does? Could we reach 90-bit *f* this way? That would be a cool Kangaroo Hopping!!! If BSGS is concerned one of possible ways is to divide the range according to the number of cpu cores and start the search from the middle of each interval using batch logic and calculating only X coordinate for the batch_size - 1 and the last one full (x,y). Make a database from the target point as large as your RAM can hold. Or since you know the size of each block do calculations to put the point closer to the middle. Maybe that way you can hit higher bits. But that depends on what time you have on your mind for that collision to happen. That's only useful for brute-forcing, however brute-forcing is un-needed for DLP problems. For BSGS this trick is also useless because it requires shifting the key by range/2 (to have the same-X mapping to 2 points), but the shift itself may move the point in the left side, which means the solution will never be found (unless you use two giant points instead of one, so zero benefit overall).

Maybe this is a stupid question, but is it possible to make the same Kangaroo have both odd and even DPs, like @AlexanderCurl does? Could we reach 90-bit *f* this way? That would be a cool Kangaroo Hopping!!! If BSGS is concerned one of possible ways is to divide the range according to the number of cpu cores and start the search from the middle of each interval using batch logic and calculating only X coordinate for the batch_size - 1 and the last one full (x,y). Make a database from the target point as large as your RAM can hold. Or since you know the size of each block do calculations to put the point closer to the middle. Maybe that way you can hit higher bits. But that depends on what time you have on your mind for that collision to happen. That's only useful for brute-forcing, however brute-forcing is un-needed for DLP problems. For BSGS this trick is also useless because it requires shifting the key by range/2 (to have the same-X mapping to 2 points), but the shift itself may move the point in the left side, which means the solution will never be found (unless you use two giant points instead of one, so zero benefit overall).