The goal is to compare how much it costs to heat up an enclosed space using miners and using other conventional heating systems. Namelly in industrial envirnoments where the conventional systems are quite expensive, from what I could already unerstand. Biofuel systems ro be more precise! So, I need to get some knowledge how fast a miner can heat up a specific volume up to s specific temperature, calculate costs, ROI, etc and then do the same thing for any other conventional system like the ones using biofuels. Wait a minute, if it's heating, why do you this round-about way? A 3500W miner will burn the same electricity as a 3500W heater and will throw out as much heat as the other! It's the law of thermodynamics, videocard, asic, oven, heater, the heat generation is the same, you can't destroy energy. You have a formula for biodiesel, quick search it's ~127,960 Btu/gal, you know the W/BTU formula, all you have to do is factor the cost of both and add the revenue for the miner. Not sure that's that straigt forward. The miner is rated at 3500W but not all that power is converted to heat, right? Good part of it will go for the computing itself, I guess. Or am I wrong? Can we consider that the total amount of input power is, in the end, converted to heat? The other issue I have is that the data I have on conventional systems are like in watts produced. But I think there are too many variables. Because if I want to prove that, in terms of costs, a miner can compete with another system, I have to account things like how much time the same volume takes to reach a specific temperature, if the conventional system is working non-stop, how many tons of biofuel it takes, etc!
The goal is to compare how much it costs to heat up an enclosed space using miners and using other conventional heating systems. Namelly in industrial envirnoments where the conventional systems are quite expensive, from what I could already unerstand. Biofuel systems ro be more precise! So, I need to get some knowledge how fast a miner can heat up a specific volume up to s specific temperature, calculate costs, ROI, etc and then do the same thing for any other conventional system like the ones using biofuels. Wait a minute, if it's heating, why do you this round-about way? A 3500W miner will burn the same electricity as a 3500W heater and will throw out as much heat as the other! It's the law of thermodynamics, videocard, asic, oven, heater, the heat generation is the same, you can't destroy energy. You have a formula for biodiesel, quick search it's ~127,960 Btu/gal, you know the W/BTU formula, all you have to do is factor the cost of both and add the revenue for the miner. Not sure that's that straigt forward. The miner is rated at 3500W but not all that power is converted to heat, right? Good part of it will go for the computing itself, I guess. Or am I wrong? Can we consider that the total amount of input power is, in the end, converted to heat? The other issue I have is that the data I have on conventional systems are like in watts produced. But I think there are too many variables. Because if I want to prove that, in terms of costs, a miner can compete with another system, I have to account things like how much time the same volume takes to reach a specific temperature, if the conventional system is working non-stop, how many tons of biofuel it takes, etc!

The goal is to compare how much it costs to heat up an enclosed space using miners and using other conventional heating systems. Namelly in industrial envirnoments where the conventional systems are quite expensive, from what I could already unerstand. Biofuel systems ro be more precise! So, I need to get some knowledge how fast a miner can heat up a specific volume up to s specific temperature, calculate costs, ROI, etc and then do the same thing for any other conventional system like the ones using biofuels. Wait a minute, if it's heating, why do you this round-about way? A 3500W miner will burn the same electricity as a 3500W heater and will throw out as much heat as the other! It's the law of thermodynamics, videocard, asic, oven, heater, the heat generation is the same, you can't destroy energy. You have a formula for biodiesel, quick search it's ~127,960 Btu/gal, you know the W/BTU formula, all you have to do is factor the cost of both and add the revenue for the miner. Not sure that's that straigt forward. The miner is rated at 3500W but not all that power is converted to heat, right? Good part of it will go for the computing itself, I guess. Or am I wrong? Can we consider that the total amount of input power is, in the end, converted to heat? The other issue I have is that the data I have on conventional systems are like in watts produced. But I think there are too many variables. Because if I want to prove that, in terms of costs, a miner can compete with another system, I have to account things like how much time the same volume takes to reach a specific temperature, if the conventional system is working non-stop, how many tons of biofuel it takes, etc!

The goal is to compare how much it costs to heat up an enclosed space using miners and using other conventional heating systems. Namelly in industrial envirnoments where the conventional systems are quite expensive, from what I could already unerstand. Biofuel systems ro be more precise! So, I need to get some knowledge how fast a miner can heat up a specific volume up to s specific temperature, calculate costs, ROI, etc and then do the same thing for any other conventional system like the ones using biofuels. Wait a minute, if it's heating, why do you this round-about way? A 3500W miner will burn the same electricity as a 3500W heater and will throw out as much heat as the other! It's the law of thermodynamics, videocard, asic, oven, heater, the heat generation is the same, you can't destroy energy. You have a formula for biodiesel, quick search it's ~127,960 Btu/gal, you know the W/BTU formula, all you have to do is factor the cost of both and add the revenue for the miner. Not sure that's that straigt forward. The miner is rated at 3500W but not all that power is converted to heat, right? Good part of it will go for the computing itself, I guess. Or am I wrong? Can we consider that the total amount of input power is, in the end, converted to heat? The other issue I have is that the data I have on conventional systems are like in watts produced. But I think there are too many variables. Because if I want to prove that, in terms of costs, a miner can compete with another system, I have to account things like how much time the same volume takes to reach a specific temperature, if the conventional system is working non-stop, how many tons of biofuel it takes, etc!